Tides & Moon Distance: Seeking Answers

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If the moon were twice as far from Earth, tidal effects would be significantly reduced, but not in a straightforward inverse square relationship. The discussion emphasizes that while gravity operates on an inverse square law, tides are influenced by multiple factors, making their calculation more complex. Participants clarify that the Sun, despite its greater mass and distance, exerts less tidal force than the Moon, illustrating that tidal effects do not strictly follow the inverse square law. The consensus suggests that tides would indeed decrease, but a precise quantitative explanation is challenging. Understanding the complexities of tidal forces is essential for accurately addressing the homework question.
kay89
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Please help me ya'll.

"If the moon was twice as far away from the Earth as it actually is, how would tides be effected?"

Any ideas/answers?

Thanks!
 
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Tides would reduce, I'm thinking.
 
vincentm said:
Tides would reduce, I'm thinking.

I think you're correct.

Kay, what sort of answer are you looking for? Will "they will reduce" suffice, or are you looking for more of an quantitative explanation?
 
Cristo, I am definitely looking for an answer that provides some meaning. This is part of a homework assignment and I am stumped!
 
kay89 said:
Cristo, I am definitely looking for an answer that provides some meaning. This is part of a homework assignment and I am stumped!

If its homework related we kindly request that you show your attempt at this question before receiving any help.
 
2 squared is = to 4
 
ray b said:
2 squared is = to 4
That's fine, but the tides do not vary with the square (or even the inverse square) of distance.
 
To help answer both the OP and explain my response to ray b, consider the Sun. The Sun is 27 million times more massive than is the Moon and is about 389 further times distant from the Earth than is the Moon. Yet the tidal forces caused by the Sun are slightly less than half those caused by the Moon.
 
a quick google shows gravity
along with a lot of other stuff works on inverse square
which is what the hint was aimed at
true that's for a point
and tides are complex with many factors
but that should be close to the correct answer
 
  • #10
ray b said:
a quick google shows gravity
along with a lot of other stuff works on inverse square
which is what the hint was aimed at
true that's for a point
and tides are complex with many factors
but that should be close to the correct answer

No. Try it for the sun.
 
  • #11
ray b said:
a quick google shows gravity
along with a lot of other stuff works on inverse square
which is what the hint was aimed at
true that's for a point
and tides are complex with many factors
but that should be close to the correct answer
Not anywhere close to the correct answer. Look at the numbers from my previous post: The Sun is 27 million times more massive than is the Moon and is about 389 further times distant from the Earth than is the Moon. If tidal effects were indeed an inverse square relationship, solar tides would be 178 times larger than lunar tides. This is not the case. Solar tides are less than half the size of lunar tides. Tidal effects are not an inverse square relationship.
 
  • #12


the tide would reduce by half, as it is twice the difference away :D
 

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