Tigonometric Identies problem help

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I need hep verifying two trig identity problems

1. (cot-csc)^2 = (1-cos)/(1+cos)


2. sin2tan2/tan2-sin2 = 1

Any help?
Thanks in advance!
 
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The easiest way to prove trig identities is to express all of the quantites in terms of sines and cosines, then start rearranging from there...
 
I have tried doing that many times ..still having no luck..
 
Could you please write out your questions again, with the variables, and all bracketing correct?

There's no way to tell is, by sin2 you mean (sin x)<sup>2</sup> or sin 2x.

Also, in your second problem, do you mean

\frac{\sin^2 x \tan^2 x}{\tan^2 x} - \sin^2 x

or something else?

Notation is important.
 
Here's a solution to the first problem:

(\cot x - \mbox{cosec} x)^2\\<br /> = \left(\frac{\cos x}{\sin x} - \frac{1}{\sin x}\right)^2\\<br /> = \frac{(\cos x - 1)(\cos x - 1)}{\sin^2 x}\\<br /> = \frac{(\cos x - 1)(\cos x - 1)}{1 - \cos^2 x}\\<br /> = \frac{(\cos x - 1)(\cos x - 1)}{(1 + \cos x)(1 - \cos x)}\\<br /> = \frac{1 - \cos x}{1 + \cos x}
 
Last edited:

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