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HallsofIvy

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George Jones

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https://www.physicsforums.com/showthread.php?p=1543402#post1543402.

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https://www.physicsforums.com/showthread.php?p=1543402#post1543402

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JesseM

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No, time dilation isn't proportional to mass difference in that way. Just use the following equation from George Jones' link, giving the ratio of a clock at the center to a clock at the surface:

https://www.physicsforums.com/showthread.php?p=1543402#post1543402

[tex]

\frac{d\tau_{centre}}{d\tau_{surf}}=\left( \frac{d\tau_{centre}}{dt}\right) \left( \frac{d\tau_{surface}}{dt}\right)^{-1} =\frac{\frac{3}{2}\sqrt{1-\frac{2GM}{c^{2}R}}-\frac{1}{2}}{\sqrt{1-\frac{2GM}{c^{2}R}-v^{2}}}

[/tex]

With G=the gravitational constant (6.67428 *10^-11 m^3 kg^-1 s^-2), M=mass of the Sun (2 * 10^30 kg), R=radius of the sun (6.955 * 10^8 m), c=speed of light (299792458 m s^-1), and v set to zero (assuming someone at rest on the surface). There's an online calculator http://www.math.sc.edu/cgi-bin/sumcgi/calculator.pl [Broken] if you need it.

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