Time Dilation Explained: T=T(P)*γ Example

Dgonzo15
Messages
14
Reaction score
0
Hello, can someone give me an explanation of the time dilation equation t=t(p)*γ? I know it's used to measure something about a difference in sense of time in different reference frames, but I don't know how to put it into context. Can someone give me an example where you would use the time dilation equation?
 
Physics news on Phys.org
Assume you have two clocks that are identical in construction.

Assume clock A is moving at 80% of the speed of light relative to clock B.

This would make γ equal to 1.6666...

t(p) would be the time that passes on clock A as measured by clock A

t is the time clock B measures for that time to pass on for clock A.

For example after 1 hr according to clock B, only 0.6 hrs will have passed on Clock B.

This assumes that the "observer" is at rest with respect to clock B.
 
Simple example, I am on the Earth with a clock that has been synchronized with another clock at some common origin (second clock on a plane moving past me at 50% speed of light). If I want to know what the clock reads on the plane in my reference frame, I have to use time dilation equation.
 
OK, so this has bugged me for a while about the equivalence principle and the black hole information paradox. If black holes "evaporate" via Hawking radiation, then they cannot exist forever. So, from my external perspective, watching the person fall in, they slow down, freeze, and redshift to "nothing," but never cross the event horizon. Does the equivalence principle say my perspective is valid? If it does, is it possible that that person really never crossed the event horizon? The...
ASSUMPTIONS 1. Two identical clocks A and B in the same inertial frame are stationary relative to each other a fixed distance L apart. Time passes at the same rate for both. 2. Both clocks are able to send/receive light signals and to write/read the send/receive times into signals. 3. The speed of light is anisotropic. METHOD 1. At time t[A1] and time t[B1], clock A sends a light signal to clock B. The clock B time is unknown to A. 2. Clock B receives the signal from A at time t[B2] and...
From $$0 = \delta(g^{\alpha\mu}g_{\mu\nu}) = g^{\alpha\mu} \delta g_{\mu\nu} + g_{\mu\nu} \delta g^{\alpha\mu}$$ we have $$g^{\alpha\mu} \delta g_{\mu\nu} = -g_{\mu\nu} \delta g^{\alpha\mu} \,\, . $$ Multiply both sides by ##g_{\alpha\beta}## to get $$\delta g_{\beta\nu} = -g_{\alpha\beta} g_{\mu\nu} \delta g^{\alpha\mu} \qquad(*)$$ (This is Dirac's eq. (26.9) in "GTR".) On the other hand, the variation ##\delta g^{\alpha\mu} = \bar{g}^{\alpha\mu} - g^{\alpha\mu}## should be a tensor...

Similar threads

Replies
14
Views
2K
Replies
16
Views
2K
Replies
54
Views
3K
Replies
10
Views
2K
Replies
46
Views
4K
Replies
9
Views
362
Replies
21
Views
2K
Replies
88
Views
7K
Back
Top