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**Homework Statement**

A cylinder (R= 0.11 m, I (center of mass)= 0.015427 kg*m2, and M= 1.48 kg) starts from rest and rolls without slipping down a plane with an angle of inclination of Theta= 26.3 deg. Find the time it takes it to travel 1.51 m along the incline.

**The attempt at a solution**

Alright, so I tried to deal with this one using torque. The torque is due to the plane's reaction to the weight of the cylinder, so...

G=m*g*r*sin(theta)=1.48*9.81*.11*sin(26.3)=.707614820587 N

G=I*a

a=G/I

a=.708/.015847=44.6529198326 rad/s^2

Now, calculate how far in radians the distance traveled is...

(2pi*1.51)/.11= 86.2509983076 rad

So, using the position equation...

s=.5at^2

t=sqrt(2s/a)

=sqrt(2*86.2509983076/44.6529198326)

=1.96549585305 s

Yeah... That's wrong... Any clue where I'm wrong? Thanks for any help you guys provide- you're all really great =)

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