Time for Light to Travel in a Gigantic Spaceship

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SUMMARY

The discussion centers on the time it takes for light signals to traverse a gigantic spaceship, specifically addressing scenarios of uniform acceleration and uniform velocity. It is established that if the spaceship is moving at a constant velocity, the time for the first signal to reach the opposite corner remains one second. However, when considering uniform acceleration, the path of light is affected by the curvature induced by acceleration, complicating the time calculation for the second signal. The equivalence principle is invoked to explain how acceleration can mimic gravitational effects on light's trajectory.

PREREQUISITES
  • Understanding of the equivalence principle in physics
  • Familiarity with concepts of light propagation in different frames of reference
  • Knowledge of uniform acceleration and uniform velocity
  • Basic grasp of relativistic effects on time and space
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  • Research the implications of the equivalence principle on light propagation
  • Study the effects of acceleration on time dilation in special relativity
  • Explore the concept of light paths in non-inertial reference frames
  • Investigate the mathematical modeling of light travel in accelerating frames
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Physicists, aerospace engineers, and students interested in relativistic physics and the behavior of light in varying gravitational and acceleration fields.

pavi_elex
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There is a very very big space-ship in which light takes 1 second to reach from one corner to other corner.
if two signals are sent one after other,what will be the amount of time for second signal to reach other corner?

If spaceship is traveling with uniform acceleration(very high for our world but very less than speed of light).
If spaceship is traveling with uniform velocity (very high for our world but very less than speed of light).

Please do not answer in numbers, the data is not sufficient for calculation. Please just describe time in detail for first signal (sending end & receiving end both) and second signal(sending end & receiving end both).
 
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pavi_elex said:
There is a very very big space-ship in which light takes 1 second to reach from one corner to other corner.
if two signals are sent one after other,what will be the amount of time for second signal to reach other corner?
You just said one second didn't you?

If spaceship is traveling with uniform acceleration(very high for our world but very less than speed of light).
What is "very less than the speed of light"? Grammatically it would be the acceleration but you cannot compare acceleration with velocity. By the "equivalence principle" an acceleration is equivalent to a local gravitational field. The light would move in a curved path and the time would depend upon the length of the path which would depend on the acceleration.

If spaceship is traveling with uniform velocity (very high for our world but very less than speed of light).
At uniform velocity, the entire ship is at rest with respect to its own coordinate frame so the answer is the same as initially- one second because you said "2(1- \frac{1}{2^{p+1}})[/tex]"


Please do not answer in numbers, the data is not sufficient for calculation. Please just describe time in detail for first signal (sending end & receiving end both) and second signal(sending end & receiving end both).
 

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