Time period of a harmonic oscillator

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VVS2000
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Homework Statement
Given is the potential energy of the harmonic oscillator: U=a|x|^n, amplititude is A
Find the time period of this harmonic oscillator
Relevant Equations
E=(1/2)m(dx/dt)^2 + a|x|^n
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Your result is written as
[tex]4A\sqrt{\frac{m}{2E}}\int_0^1 \frac{dx}{\sqrt{1-x^n}}[/tex]
where amplitude A is
[tex]A=(\frac{E}{a})^{\frac{1}{n}}[/tex]
 
anuttarasammyak said:
Your result is written as
[tex]4A\sqrt{\frac{m}{2E}}\int_0^1 \frac{dx}{\sqrt{1-x^n}}[/tex]
where amplitude A is
[tex]A=(\frac{E}{a})^{\frac{1}{n}}[/tex]
No, I have'nt written 4A. It's 4. A is inside the root in the denominator.
But how do you solve that integral?
 
anuttarasammyak said:
Your result is written as
[tex]4A\sqrt{\frac{m}{2E}}\int_0^1 \frac{dx}{\sqrt{1-x^n}}[/tex]
where amplitude A is
[tex]A=(\frac{E}{a})^{\frac{1}{n}}[/tex]
No, I have'nt written 4A. It's 4. A is inside the root in the denominator.
But how do you solve that integral?
 
I made a replacement of x/A ##\rightarrow## x.

The definite integral is a function of ##\Gamma## functions of ##\frac{1}{n}##.
 
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Harmonic oscillator in classical physics are not systems subject to an force/ente proportional to its "displacement"? So n shouldn't be two?
Or it is not a harmonic oscillator?
 
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As noted by LCSphysicist (#6), this is NOT a harmonic oscillator (except when n=2). The word 'harmonic' is specifically used twice. Is there a possibility this is a 'trick' question?

A harmonic oscillator is one which has a restoring given by:
##\vec F = -k\vec x ##
If I were answering I would demonstrate that only n=2 gives a harmonic oscillator. (Hint, what is the relationship between ##\vec F ## and U?)

Then express in the usual SHM equation format:
##\frac {d^2 x }{dt^2} + \omega^2 x = 0##
You then get the period from ##\omega##.

Just a thought.