Time Period of Halved Simple Pendulum

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Halving the length of a simple pendulum results in a change in its time period, which can be calculated using the formula T = 2π√(L/g). When the length is halved (L2 = L1/2), the relationship between the periods T1 and T2 can be expressed as T1/T2 = √(L1/L2). Substituting L2 into the equation gives T1/T2 = √(2), indicating that the time period is reduced. Thus, the time period of the pendulum decreases when its length is halved. Understanding this relationship is essential for solving pendulum problems effectively.
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when we half the length of simple pendulum what will be its time period?please reply
 
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This is something that is hard to tell you without doing the problem for you.

Since you are not given actual values, you have to use variables.
You are told that L1/L2=2 (L2 is half of L1), you need to find T1/T2, you know the formula that relates the period of a pendulum to it's length.
 
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