# Time Period of pendulum on another planet? Given gravity

## Homework Statement

9. A simple pendulum on Earth has a period of 6.0 seconds. What would the period of this pendulum be on Jupiter, if the acceleration of gravity on the surface of Jupiter is 26 m/s2

A. 2.3 sec
B. 3.7 sec
C. 6.0 sec
D. 15.6 sec

## Homework Equations

T=2pi * sqrt (L/g) Where L= Length of the pendulum

g=grav

## The Attempt at a Solution

i know that 6.0s=2pi * (L/9.8) <-since that is the gravity on earth.
and T= 2pi* (L/9.8)

maybe, 6= 2pi * (L/9.8) ? But then ill be solving for L...

olivermsun
They're asking you what T would be, so that is what you need to solve for under Jupiter conditions.

What changes on the right hand side when you move to Jupiter?

maybe sub "6on Earth" somewhere, but i dont know how to word that into a mathmatical form. like present the ratio between earth and jupiter somewhere

im doing 6= 2pi sqrt(L/26)

6^2=4pi^2 L/26

i keep getting 23. which is not an option.

SteamKing
Staff Emeritus
Homework Helper
The period is 6 sec. on earth. It will not be 6 sec on Jupiter. Don't you have enough information to calculate the period on Jupiter? (Hint: use algebra)

OKAY, cross multiply, try number 3:

6sec = Xsec x=15.91, which again, is not an option.
/9.8 / 26

so now i have solved for the LENGTH of the pendulum on earth: L= 6^2/4pi^2 * 9.8

(i think thats right) and used 870, the Length and solved for T on Jupiter.

I get 36.34. Hmm, the squroot of 36.34 is 6. ahhh!

SteamKing
Staff Emeritus