9. A simple pendulum on Earth has a period of 6.0 seconds. What would the period of this pendulum be on Jupiter, if the acceleration of gravity on the surface of Jupiter is 26 m/s2
A. 2.3 sec
B. 3.7 sec
C. 6.0 sec
D. 15.6 sec
T=2pi * sqrt (L/g) Where L= Length of the pendulum
The Attempt at a Solution
i know that 6.0s=2pi * (L/9.8) <-since that is the gravity on earth.
and T= 2pi* (L/9.8)
maybe, 6= 2pi * (L/9.8) ? But then ill be solving for L...
i have no idea what to do if any one could please help me/explain the concepts.