- #1
msn56
- 17
- 0
Hi Guys :
I have been reading about torque and gears and not being an engineer or physicist would like to know if my thinking is correct in the following example
Ok so Say I have a hydraulic motor and it generates 3000 ft lbs of torque and it is going to be turned at 650 RPM (tractor PTO) please see pic to explain this
Coming out of that motor is a 1 " shaft. Therefore the torque at the 1" shaft is 3000. Ok if I put a 2 " pulley on that shaft its torque would be 1/2 of that or 1500.
NOw I will connect the 2" pulley to a ten inch one by chain. THat 10 inch pulley also has a one inch shaft So now the torque of the the one inch shaft on that the 10" pulley woudl be 5 x as much or 7500 . If I put a 2" gear on the end of that one inch shaft I again lose half my torque and am down to 3750.
ONce again I connect that 2" gear to a 10 inch one and that would give me 5 x as much torque - if I had a one inch shaft coming out of it 0r 3750 *5 = 18750.
However instead of a one inch shaft I will have a 3 inch pipe to wrap the cable on so that will have 1/3 as much or 6250 lbs.
Are these assumptions correct? Really appreciate any help
I have been reading about torque and gears and not being an engineer or physicist would like to know if my thinking is correct in the following example
Ok so Say I have a hydraulic motor and it generates 3000 ft lbs of torque and it is going to be turned at 650 RPM (tractor PTO) please see pic to explain this
Coming out of that motor is a 1 " shaft. Therefore the torque at the 1" shaft is 3000. Ok if I put a 2 " pulley on that shaft its torque would be 1/2 of that or 1500.
NOw I will connect the 2" pulley to a ten inch one by chain. THat 10 inch pulley also has a one inch shaft So now the torque of the the one inch shaft on that the 10" pulley woudl be 5 x as much or 7500 . If I put a 2" gear on the end of that one inch shaft I again lose half my torque and am down to 3750.
ONce again I connect that 2" gear to a 10 inch one and that would give me 5 x as much torque - if I had a one inch shaft coming out of it 0r 3750 *5 = 18750.
However instead of a one inch shaft I will have a 3 inch pipe to wrap the cable on so that will have 1/3 as much or 6250 lbs.
Are these assumptions correct? Really appreciate any help