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## Main Question or Discussion Point

**What I have:**

- A hollow cylinder filled 1/3 its dia with slurry.
- Wt of cylinder is 987251 pounds
- Wt of slurry is 358157 pounds

- Radius of cylinder = 8.5 ft.
- RPM = 7.5
- Time taken = 20 seconds

**What I need is :**

- Torque required to roate the cylinder
- Torque required to rotate the slurry inside along with the cylinder

**My try:**

- Mass = Wt / accn due to gravity = 987251 / 32.2 = 30659.9
*(where accn.due to gravity is in ft/sec^2)* - Torque required to rotate cylinder is Tcyl= (30659.9 * 8.5^2 * 2* Pi*RPM)/(60*20)

**How to arrive for both combined..**

- Is it the same procedure too? That is calculate torque reqd for the slurry too and then add both ?

Instead, can we use Torque = Force*Radius principle to arrive at the Torque required for rotating the slurry - How to calculate the start up torque
- Remember having learnt some perpendicular axes theorem or parallel axes thoerom., do those apply ????

Any other method towards solving this ??

**Any help is much appreciated**

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