I'm currently working on two homework problems that are giving me a bit of trouble. Torque has been a difficult chapter for me. I'm going to worry about just this one for now: Question 1: Calculate FA and FB for the beam shown in Fig. 9-49. The downward forces represent the weights of machinery on the beam. Assume the beam is uniform and has a mass of 210 kg. Fig. 9-49 shows: http://grab.by/Byt I know that the net external force must be zero: SUM of Forces = 0 I also know that the net external torque must be zero: SUM of Torque = 0 So I've set up my equation for Torque, where T is Torque: T = Force x Distance from the Pivot So if I make my pivot the point at FA, shouldn't I have: 0 = - T(4300N x 2.0M) - T(3100N x 6.0M) - T(2200N x 9.0M) + Tboard + TFB Solving for the Torque of the Board: Tboard = 210Kg * 9.8 m/s2 * 5M = 10290 Plugging in all the Torques, 10FB being 10 (distance from FA) x Force (FB) 0 = -8600 - 18600 - 19800 + 10290 + 10FB When I solve for FB however, and plug that force back into the equation, I'm not getting zero. I'm lost as to where I'm going wrong.