Torque on a block with acceleration 4i-3j.

AI Thread Summary
The discussion centers on calculating the torque acting on a 2.0-kg block with an acceleration of 4i-3j after 2.0 seconds. The block starts from rest at a position 3.0 m along the positive x-axis. Participants emphasize using the definition of torque, τ = F × r, and suggest considering the block's position at the end of the time interval to determine the correct radius vector. The moment of inertia is calculated using the mass and radius squared, and the angular acceleration is derived from the linear acceleration. The conversation highlights the importance of accurately determining the block's final position to solve the problem effectively.
chouZ
Messages
11
Reaction score
0

Homework Statement


A 2.0-kg block starts from rest on the positive x-axis 3.0 m from the origina and thereafter has an acceleration given by a = 4i-3j. The torque, relative to the origin acting on it at the end of 2.0 s is:


Homework Equations



linear acceleration= (radius)(angular acceleration)

torque= (moment of Inertia)(angular acceleration)

The Attempt at a Solution



I found the angular acceleration using the formula above
moment of Inertia=(mass)(radius square)
Then find the torque using the formula above

that's not it...help!...:frown:
 
Physics news on Phys.org
HINT: Definition of torque;

\tau = \vec{F}\times \vec{r} = m\vec{a}\times\vec{r}
 
Hint: Where is the block at the end of 2 seconds?
 
thanks for the help guys...
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top