Tossing upward with air resistance

AI Thread Summary
The discussion focuses on calculating the distance an object travels upward while considering air resistance. The original approach using the kinematic equation vf^2=vi^2+2ad is questioned, particularly regarding the inclusion of frictional forces. It is clarified that the acceleration "a" should account for both gravity and the drag force, rather than just gravity alone. Participants suggest using Newton's Second Law to derive the correct acceleration. Understanding these forces is crucial for accurately determining the distance traveled.
jvileisis
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Could someone tell me if my approch to this is correct? I am given the change in vertical v final(zero), v initial, mass, and frictional coefficient. The question askes for distance. I set up the equation vf^2=vi^2+2ad(mg(frictional coefficent))
 
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I don't understand what you mean by that equation. If you are multiplying the 2ad term by the force of friction from the air then you are incorrect.

That kinematic equation is still valid in its normal form. The difference is that "a" will not be the acceleration caused by gravity, but it will be the acceleration caused by the sum of gravity and the drag force.

HINT: Can you find this acceleration starting from Newton's Second Law?
 

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