Total energy of an oscillator

  • Thread starter fruitl00p
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  • #1
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Homework Statement



A mass M is suspended from a spring and oscillates with a period of .940s. Each complete oscillation results in an amplitude reduction of a factor of .96 due to a small velocity dependent of frictional effect. Calculate the time it takes for the total energy of the oscillator to decrease to .50 of its initial value.

Homework Equations



unsure.... A=Ao*factor^N

The Attempt at a Solution



I am unsure how to approach this. I did

log .50 = t log(.96)^2
t= log(.50)/log(.96)^2
t=8.48 s

but that was incorrect. Can someone please tell me what I am doing wrong?
 

Answers and Replies

  • #2
AlephZero
Science Advisor
Homework Helper
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In you equation

log .50 = t log(.96)^2,

"t" isn't the time in seconds, it's the number of cycles of oscillation when the energy has decayed to .50 of the original value.

You want to time for 8.48 cycles with a period of 0.940 sec/cycle.
 
  • #3
94
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Oh, I see now. I think I can handle the equation from here. Well, I'm going to attempt the problem again to make sure :smile:
 
  • #4
94
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Yes, I got it correct, thank you AlephZero!
 

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