Total interior and exterior charge of a hollow sphere?

AI Thread Summary
A hollow conducting sphere with an inner radius R and outer radius 1.5R contains a +40nC point charge at its center. According to Gauss's Law, the total charge on the inner surface of the sphere will equal -40nC, while the outer surface will have a charge of +40nC to maintain overall neutrality. The charge density calculated, σ = 3.18*10^-7 C/m^2, is not directly relevant to the question about total charge. The electric field outside the sphere is influenced by the charge on the outer surface, which behaves as if all the charge were concentrated at the center. Understanding these relationships is key to solving the problem correctly.
KoontzyN
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Homework Statement


A hollow conducting sphere has inner radius R and outer radius 1.5R. A +40nC point charge is placed at the center. What is the total charge on the interior and exterior walls of the sphere?

R=10cm

Homework Equations


Gauss's Law
σ = Qenc/A

The Attempt at a Solution


I'm not too sure where to start. I know Gauss's Law for a sphere is E=Qenc/4πε0r2 , but I don't know where to go from here.

I also know that to find the charge density σ = Qenc/A. Plugging in the knowns I get σ= 3.18*10^-7 C/m^2. I'm not sure if that relates to the problem at all. Any help is appreciated.

 
Physics news on Phys.org
You are not asked for charge density.

How does the charge on the outer surface compare with that on the inner surface?
Consider the field outside the sphere. How is that affected by the charges on the sphere?
 
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