Total work/effort/energy spent to climb a hill

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SUMMARY

The discussion centers on calculating the total work and energy expenditure for a person climbing a hill, specifically a 60 kg individual ascending a vertical height of 200 meters over a horizontal distance of 3000 meters. The primary formula used is W = mgh, yielding a minimum work of 120,000 J. However, participants emphasize that this calculation does not account for horizontal movement and the inefficiencies of the human body, which can lead to a significantly higher calorie expenditure. A more comprehensive approach includes factors like friction and metabolic efficiency, ultimately suggesting that the total energy required could be around 151 kcal when considering a 20% efficiency rate.

PREREQUISITES
  • Understanding of basic physics concepts such as work, energy, and potential energy.
  • Familiarity with the formula W = mgh for calculating gravitational work.
  • Knowledge of metabolic efficiency and its impact on energy expenditure.
  • Basic understanding of friction and its role in mechanical work calculations.
NEXT STEPS
  • Research the impact of incline angles on work done using the formula W = Fdx + mgh.
  • Explore the relationship between metabolic efficiency and energy expenditure during physical activities.
  • Learn about the effects of friction coefficients on work calculations in real-world scenarios.
  • Investigate empirical studies on energy expenditure during hiking and climbing.
USEFUL FOR

This discussion is beneficial for physics students, fitness enthusiasts, and anyone interested in understanding the mechanics of energy expenditure during physical activities such as hiking or climbing.

  • #31
Merlin3189 said:
I'm not sure how his muscles pull him up, or how forces come from your body. I can see how you apply forces to other objects, but not how you apply a net force to yourself.
Have you come across Newton's third law?

Anyhow, if I understand your answers, I should be able to run up an icy hill much easier than up a rough hill:
View attachment 97267

the third law says about action and reaction but of course these two are applied to different bodies. like i create and push the ground and the ground pushes back.
also in a theoretical model yes, because in reality you would slide down and the go back and try again so the effort would be much more. on ice there is less friction but then you have the slippery aspect :P and as we know we walk and move around thanks to friction, that's why you can't move up an ice hill because the friction is minimum
 
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  • #32
Stella.Physics said:
the third law says about action and reaction but of course these two are applied to different bodies. like i create and push the ground and the ground pushes back.
And I think, the ground pushing back is the forces of friction and normal reaction. You pushing down on the ground is opposed by the ground pushing up on you, and you pushing backwards on the ground is opposed by friction pushing forwards on you. Which is where I start to get concerned about the work we do against friction when walking.

Anyhow, this is getting a bit away from ur original Q. My point was simply that the work done going horizontally was not work against ground friction, but work lifting legs and feet over the ground.
 

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