Transfer function Of A Highpass Filter

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To transform the transfer function of a highpass filter from H(w) = jwR2 / [ (R1R2/L) + jw(R1 + R2)] to H(w) = [R2/(R1+R2)][jw/(jw+wc)], one can factor R2 from the numerator. By extracting (R1 + R2) from the denominator, it simplifies to [{R1R2/L(R1+R2)} + jw](R1 + R2). The corner frequency, wc, is defined as wc = R1R2/L(R1 + R2). The transformation shows that the denominator can be expressed in the desired form, confirming the equivalence of the two representations. This method effectively clarifies the relationship between the components and the highpass filter's characteristics.
jyde
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Please how do i transform this transfer function of a highpass filter

H(w) = jwR2 / [ (R1R2/L) + jw(R1 + R2)] to

H(w) = [R2/(R1+R2)][jw/(jw+wc)]

wc is the corner freq.

The circuit consists of a voltage source Vs(t) ,R1 in series with R2||L,Vo collected on R2.

Thanks.
 
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jyde said:
Please how do i transform this transfer function of a highpass filter

H(w) = jwR2 / [ (R1R2/L) + jw(R1 + R2)] to

H(w) = [R2/(R1+R2)][jw/(jw+wc)]

wc is the corner freq.

The circuit consists of a voltage source Vs(t) ,R1 in series with R2||L,Vo collected on R2.

Thanks.

Welcome to PF, jyde! :smile:We can draw R2 from the nominator.

What do you get for the denominator if you extract (R1+R2)?
 
The denominator will then be [{R1R2/L(R1+R2)} + jw](R1+R2)
 
Good.

So let's define wc=R1R2/L(R1+R2).

Does [{R1R2/L(R1+R2)} + jw] look like (jw+wc)?
 
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