Transformer, AC Source, and a Battery

AI Thread Summary
The discussion centers on generating an output signal vout = vs + VB using an AC signal generator, a transformer with a turns ratio of n = 1, and a battery. Participants clarify that the battery can be positioned in either the top or bottom leg of the circuit without affecting the output, as it simply adds a DC offset. The concept of an ideal voltage source with zero internal resistance is highlighted, explaining that this configuration does not alter the AC signal but only shifts it. The simplicity of the solution is acknowledged, reinforcing the understanding of how AC and DC components interact in the circuit. Overall, the circuit design effectively combines AC and DC signals.
drumercalzone
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Homework Statement



Using an AC signal generator vs, a transformer with turns ratio n = 1, and a battery VB, sketch a circuit that will generate the output signal vout = vs + VB

Homework Equations



\frac{V_2}{V_1} = \frac{N_2}{N_1}

The Attempt at a Solution


N9ZY6l.jpg


Here's my sketch, but I feel like I'm missing something conceptually. Because if this were the case, couldn't the battery be on the bottom wire since we're dealing with an AC signal source?
 
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drumercalzone said:

Homework Statement



Using an AC signal generator vs, a transformer with turns ratio n = 1, and a battery VB, sketch a circuit that will generate the output signal vout = vs + VB

Homework Equations



\frac{V_2}{V_1} = \frac{N_2}{N_1}

The Attempt at a Solution


N9ZY6l.jpg


Here's my sketch, but I feel like I'm missing something conceptually. Because if this were the case, couldn't the battery be on the bottom wire since we're dealing with an AC signal source?

Looks fine to me. The battery can go in either the bottom or top leg of the secondary. It will still add a DC offset to the output.
 
Thank you for your help! It just seemed too easy!
 
You are welcome.

One of the things that makes this work in this example, is that the internal resistance of an ideal voltage source is zero. So putting the DC voltage source in series with the transformer does nothing but add an offset voltage.
 
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