Transformers and Power: How Can Impedance Matching Improve Power Transfer?

[gneill]

I see..I appreciate the big picture. So the reason why you changed the imaginary part seen from primary to load to "-j.16400" is due to the maximum power theorem correct?

Right. The load inductance is reflected into the primary as inductance (positive impedance value). The negative impedance of the capacitor cancels it when they are added together (they are in series). So the voltage source "sees" a purely resistive load.

 

[Aristotle]

Right. The load inductance is reflected into the primary as inductance (positive impedance value). The negative impedance of the capacitor cancels it when they are added together (they are in series). So the voltage source "sees" a purely resistive load.

Mind is blown Thank you again.

 

[Shenanigan_engineer]

I

I must be missing something conceptually. How did you get this to a capacitor. This is what I tried

 

[gneill]

IView attachment 96947
I must be missing something conceptually. How did you get this to a capacitor. This is what I tried

Your first formula describes the impedance that the transformer presents to the rest of the primary circuit. Calculate that impedance without including the rest of the primary circuit.

Once you've done that you can consider the maximum power theorem for the new equivalent circuit in conjunction with the source voltage, its resistance, and whatever series device you choose to insert. Note that the equivalent impedance that the load presents to the primary is inductive. You choose a capacitor to add in series so that the maximum power transfer can be attained.

 

[Shenanigan_engineer]

That helps a lot, after applying that to the problem it was a lot clearer. Thanks a ton.