Transient (unsteady) heat transfer over a sphere

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SUMMARY

This discussion focuses on transient heat transfer analysis for a solid steel sphere with a diameter of 1 cm, initially at 15 ºC, placed in a flow at 60 ºC with a convection heat coefficient of 2000 W/(m²K). The Lumped Capacitance method is applied to derive the temperature variation over time, resulting in the equation (T(t) - Tinf) / (T0 - Tinf) = exp(-b * t), where b = (h*A)/(rho*V*c) = 0.354. The Biot number calculated is 0.15, confirming the validity of the assumptions for using the Lumped Capacitance method. The discussion also addresses the impact of adding a 4 mm plastic layer on the sphere's heat transfer characteristics, emphasizing the need to adjust the heat transfer coefficient to account for the additional thermal resistance.

PREREQUISITES
  • Understanding of transient heat transfer principles
  • Familiarity with the Lumped Capacitance method
  • Knowledge of Biot number calculations
  • Basic concepts of thermal conductivity and heat transfer coefficients
NEXT STEPS
  • Study the derivation and application of the Lumped Capacitance method in heat transfer
  • Learn how to calculate temperature gradients within solid objects
  • Research the effects of thermal resistance in multi-layer systems
  • Explore the implications of Biot number on heat transfer analysis
USEFUL FOR

Mechanical engineers, thermal analysts, and students studying heat transfer who are interested in transient thermal analysis and the effects of insulation on heat transfer rates.

diegojolin
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I AM DOING A PROBLEM ABOUT TRANSIENT HEAT TRANSFER AND IT SAYS:

"A solid sphere of steel has 1 cm of diameter and a initial temperature of T0 =15 ºC. It is placed into a flow of Tinf = 60 ºC where the convection heat coefficient is h = 2000 W/(m^2K):

(Density of steel rho = 7832 Kg/m^3 ; Specific heat c= 434 J / (Kg K) ; Thermal Conductivity of Steel Ks = 63.9 W / ( m K )

1. First develop an expression for the variation with time of the temperature of the sphere (Lumped Capacitance method).

2. Check that the assumptions made to use that method were right and give the order of magnitude of the temperature gradients inside the sphere

3. Compute the time required for the sphere to get to a value of 50ºC when a plastic layer of 4 mm of thickness is placed over the sphere. The thermal conductivity of this layer is 0.3 W/ (m K) "

I have been able to integrate the transient formula this way :

b = (h*A)/(rho*V*c) = 0.354

where A = 4*pi*r^2 and V = 4/3 * pi * r^3

( T(t) - Tinf ) / (T0 - Tinf) = exp ( -b * t)

This expression seems to be valid since my professor has integrated himself several times at class.

To check the assumptions I just computed the Biot number and I saw that I has a value of 0.15 which more or less acceptable.

But how can I give an estimate of the order of magnitude of the temperature gradients??

and even more, how changes this problem when I add a plastic layer? how can I compute the value required?
 
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For part 3, note that the density and specific heat were not supplied for the plastic coating. Therefore the only thing left to do is to modify the supplied heat transfer coefficient to compensate for the added resistance of the coating. It has the effect of lessening the Biot number.
 

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