1. The problem statement, all variables and given/known data A furnace wall is made up of 3 layers: 1. 4mm layer of material with thermal conductivity of 52 W/m.K 2. 2mm layer of material with thermal conductivity of 20 W/m.K 3. 1mm layer of material with thermal conductivity of 3 W/m.K There is an air gap between layers 1&2 with a thermal resistance of 0.16 K/W. The temperature at the inner surface of layer 1 is 873.15 K The ambient temperature outside layer 3 is 343.15 K The heat transfer coefficient from outside surface to surroundings is 17 W/m^2 .K Find the following: 1. Rate of heat loss per square metre of outside surface (heat flux) 2. Temperature at each interface of wall, including outside surface temperature. 2. Relevant equations h=q/ΔT h = Heat transfer coefficient (in W/m^2 .K) q = Heat flux (in W/m^2) ΔT = Change in temperature (in K) q=(kΔT)/L q = Heat flux (in W/m^2) k = Thermal conductivity (in W/mK) ΔT = Change in temperature (in K) L = Thickness of material (in m) R=L/kA R = Thermal resistance (in K/W) L = Thickness of material (in m) k = Thermal conductivity (in W/mK) A = Area (in m^2) q=ΔT/[(L1/k1)+(L2/k2)+(L3/k3)] q = Heat flux (in W/m^2) ΔT = Change in temperature between outer surfaces (in K) L1 = Thickness of layer 1 (in m) L2 = Thickness of layer 2 (in m) L3 = Thickness of layer 3 (in m) k1 = Thermal conductivity of layer 1 (in W/mK) k2 = Thermal conductivity of layer 2 (in W/mK) k3 = Thermal conductivity of layer 3 (in W/mK) 3. The attempt at a solution Found the following equation but do not know how to remove A (area) to find q (heat flux). 3147.064q=28111200-8486.4A Any useful hints would be much appreciated!