Translation and rotation of quadric surface

[songoku]

Homework Statement

This is not homework. I try to study calculus by myself using James Stewart book and below is part of text that I want to ask about

Relevant Equations

Not sure

I want to ask how $Ax^2+By^2+Cz^2+Dxy+Eyz+Fxz+Gx+Hy+Iz+J=0$ can be brought to $Ax^2+By^2+Cz^2+J=0$ or $Ax^2+By^2+Iz=0$ using translation and rotation. There is no explanation in the book. What kind of translation and rotation are needed?

Thanks

 

[pasmith]

(1) The constants in the various forms are not the same.

(2) The variables int he various forms are not the same.

The general form can be written <br /> \begin{pmatrix} x &amp; y &amp; z \end{pmatrix} \begin{pmatrix} A &amp; \frac12D &amp; \frac12 F \\ \frac12 D &amp; B &amp; \frac12 E \\ \frac12 F &amp; \frac12 E &amp; C \end{pmatrix} \begin{pmatrix} x \\y \\ z \end{pmatrix} + \begin{pmatrix} G &amp; H &amp; I \end{pmatrix} \begin{pmatrix} x \\ y \\ z \end{pmatrix} + J = \mathbf{x}^TM\mathbf{x} + \mathbf{b}^T \mathbf{x} + J = 0. Now M is symmetric, so its eigenvalues are real and it has a basis of orthogonal eigenvectors; thus there exists a rotation (ie. a matrix R with determinant 1 such that R^{-1} = R^T) such that R^{-1}MR is diagonal. What happens if you now set \mathbf{x} = R\mathbf{X} in the general form and complete the squares in each variable for which the corresponding diagonal entry of R^{-1}MR is non-zero?

 

[e_jane]

I try to study calculus by myself using James Stewart book...

I want to ask how $Ax^2+By^2+Cz^2+Dxy+Eyz+Fxz+Gx+Hy+Iz+J=0$ can be brought to $Ax^2+By^2+Cz^2+J=0$ or $Ax^2+By^2+Iz=0$ using translation and rotation. There is no explanation in the book.

They took out that whole chapter? Nice! I remember *hating* that chapter.

 

[songoku]

(1) The constants in the various forms are not the same.

(2) The variables int he various forms are not the same.

The general form can be written <br /> \begin{pmatrix} x &amp; y &amp; z \end{pmatrix} \begin{pmatrix} A &amp; \frac12D &amp; \frac12 F \\ \frac12 D &amp; B &amp; \frac12 E \\ \frac12 F &amp; \frac12 E &amp; C \end{pmatrix} \begin{pmatrix} x \\y \\ z \end{pmatrix} + \begin{pmatrix} G &amp; H &amp; I \end{pmatrix} \begin{pmatrix} x \\ y \\ z \end{pmatrix} + J = \mathbf{x}^TM\mathbf{x} + \mathbf{b}^T \mathbf{x} + J = 0. Now M is symmetric, so its eigenvalues are real and it has a basis of orthogonal eigenvectors; thus there exists a rotation (ie. a matrix R with determinant 1 such that R^{-1} = R^T) such that R^{-1}MR is diagonal. What happens if you now set \mathbf{x} = R\mathbf{X} in the general form and complete the squares in each variable for which the corresponding diagonal entry of R^{-1}MR is non-zero?

I will try first and update what I have done.

They took out that whole chapter? Nice! I remember *hating* that chapter.

Can you maybe tell me the name of the chapter or anything related to the transformation of quadric surface so I can learn the basic?

Thanks

 

[e_jane]

They took out that whole chapter? Nice! I remember *hating* that chapter.

Can you maybe tell me the name of the chapter or anything related to the transformation of quadric surface so I can learn the basic?

I sold that textbook back to the university's bookstore about thirty years ago. Sorry.