Transposing and Inversing Matrices

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Homework Statement


Prove that if A is an invertible matrix, then A*AT and AT*A are also invertible.


Homework Equations


(AT)-1=(A-1)T
(AB)T=ATBT

The Attempt at a Solution


I just can't wrap my brain around this one. I know that I have to multiply a matrix by its inverse to get the identity matrix, but I don't know where to go from there.
 
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(AB)^T=B^T*A^T. Not A^T*B^T. Now that we've gotten past that, what would be the inverse of A*A^T given both of the elements in the product have inverses?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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