Triangle Inequalities Relationship

ait.abd
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I know the following
|x|-|y| \leq |x+y| \leq |x| + |y|
where does |x-y| fit in the above equation?
 
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How about x+(-y)?

also, notice that there is a sort of better result, but I like the way you wrote it, makes it easier to remember and figure out what might be needed in a problem. But sometimes the left inequality is written:

||x|-|y||\le|x+y|

Just so that you understand when many other people write this.
 
algebrat said:
How about x+(-y)?

also, notice that there is a sort of better result, but I like the way you wrote it, makes it easier to remember and figure out what might be needed in a problem. But sometimes the left inequality is written:

||x|-|y||\le|x+y|

Just so that you understand when many other people write this.

So

|x|-|y| \leq |x+y| \leq |x| + |y|

and

|x|-|y| \leq |x-y| \leq |x| + |y|.

I think we can't say anything about the relationship between|x+y| and |x-y|,
and in between ||x|-|y||and |x|-|y|.
 
|x+y|\ge||x|-|y||\ge|x|-|y|
 
ait.abd said:
I think we can't say anything about the relationship between|x+y| and |x-y|,

You can prove this pretty quickly by plugging numbers in, or just notice that the replacement ##y \mapsto -y## yields the other, hence the only possible relation is equality, which is clearly false.
 
ait.abd said:
I think we can't say anything about the relationship between|x+y| and |x-y|,
and in between ||x|-|y||and |x|-|y|.

if x and y have like signs then lx+yl ≥ lx-yl if unlike signs then lx+yl≤ lx-yl , check it out and always llxl-lyll >= lxl-lyl
 
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