- #1

Fusilli_Jerry89

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## Homework Statement

A bowling ball mass 3.2 kg rolls west at 4.2 m/s striking a stationary ball mass 3.2 kg. After the collision the second ball travels in a direction 24 degrees south of west at 3.6 m/s. Whats the first balls speed after the collision.

## Homework Equations

mv+mv=mv+mv

## The Attempt at a Solution

p1=13.44 kgm/s W

p2=0

p1'=?

p2'=11.52 kgm/s 24 degrees south of west

13.44 W - 11.52 24 S of W = p1'

I then drew the resulting vectors and subtracted them getting a triangle with the lengths 13.44, 11.52, and 5.52 with an angle of 24 degrees between 13.44 and 11.52. My question is that when i use sine law to get the two remaining angles, all the angles only add up to 160 degrees. What's the deal here? (I got the length of the last angle via: x^2=13.44^2+11.52^2-2(13.44)(11.52)cos24)