# Triangles in hexagon

1. Jan 12, 2013

### Numeriprimi

I have hexagon ABCDEF (30 cm2) and point M inside.
True: ABM = 3 cm2; BCM = 2 cm2; DEM = 7 cm2 ; FEM = 8cm2

How can I determine area of others two triangles? I know their total area, but how individually?

Thanks very much and if you don't understand, write, I will try to write better.
Poor Czech Numeriprimi

2. Jan 12, 2013

### Simon Bridge

You exploit the symmetry of the hexagon ... did you sketch it out?
Point M is closest to B and C, closer to B than C - right?

Can you find the length of the line segments radiating from M in terms of the areas you know?

3. Jan 13, 2013

### Numeriprimi

How can I exploit symmetry?
And yes, it is right, but but what good is it useful?
I don't understand your third question.... What length from M?

4. Jan 13, 2013

### HallsofIvy

The problem, as stated, does not suggest that this is a "regular" hexagon and so does not imply any "symmetry".

Numeri Primi, it is easy, as you say, to see that the total area of the two remaining triangles is 30- (3+ 2+ 7+ 8)= 30- 20= 10. But there is NO way to determine the area of the two triangles separately. It is possible to construct many different (non-symmetric) hexagons having the given information but different areas for the last two triangles.

Last edited by a moderator: Jan 14, 2013
5. Jan 14, 2013

### Simon Bridge

That's a good point... though the question would seem somewhat unfair if it were not.