Trick Question? (Making a solution)

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A student inquires about the feasibility of creating a 0.5 M KNO3 solution at 12 degrees C, questioning the impact of temperature on solubility. Discussions reveal that temperature affects reaction rates and solubility, with lower temperatures potentially reducing the ability to dissolve KNO3. The solubility constant (Ksp) for KNO3 at this temperature is also considered, with suggestions to consult reliable sources for specific solubility data. Calculations indicate that a 0.5 M solution corresponds to 0.5 moles of KNO3 per liter, prompting further exploration of Ksp values. The conversation concludes with appreciation for the diverse insights shared on the topic.
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Homework Statement


A student wishes to make a 0.5 M KNO3 solution at 12 degrees C. Is this possible? Explain, and show calculations to support your answer.
[This is a question related to a solubility lab]


Homework Equations


In my experiment, I saw that as temperature decreased and as volume increased, molarity decreased, but I don't know if temperature is actually related to this observation.


The Attempt at a Solution


.5 M solution = .5 moles KNO3/1L, right?
Does temperature affect this?
 
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Temperature effects any ability to make any kind of solution, mainly because reactions slow down with a decrease in temperature.

As for molarity, bond forming and other reactions take longer to occur because of the cold. You might want to look up the freezing point of KNO3 if possible.

And to answer your question, yes. a 0.5 M solution of KNO3 means 0.5 moles per 1 L soln.
 
needphyshelp said:

Homework Statement


A student wishes to make a 0.5 M KNO3 solution at 12 degrees C. Is this possible? Explain, and show calculations to support your answer.
[This is a question related to a solubility lab]


Homework Equations


In my experiment, I saw that as temperature decreased and as volume increased, molarity decreased, but I don't know if temperature is actually related to this observation.


The Attempt at a Solution


.5 M solution = .5 moles KNO3/1L, right?
Does temperature affect this?

What's the solubility constant of KNO3 AT 12 degrees C?
 
How can I calculate Ksp without having the concentrations? I know Ksp = [K+][NO3-]... would I just plug in .5 to get Ksp and go from there?
 
needphyshelp said:
How can I calculate Ksp without having the concentrations? I know Ksp = [K+][NO3-]... would I just plug in .5 to get Ksp and go from there?

I would think so; you have 0.5mol of KNO3 assuming 1L of solution, so that means you have 0.5mol [K+] and 0.5mol [NO3-]. This would give you a Ksp of 0.25, but then again it's been a while since I've done this.
 
This is pretty well soluble salt, so it will not have Kso listed. However, if you will check CRC handbook or some other, similar source, you should be able to find what is KNO3 solubility in grams per 100 g of water - check, if it is not less then 0.5M.
 
Thank you all so much for your input - I now have a few different ways to look at this problem. I really appreciate it!
 
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