Tricky Kinematics Problems - Desperately

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Homework Statement


I am new to this board, but I am at my wits end trying to solve this problem. If anyone could provide a somewhat detailed solution i would forever be in debt, thanks!

One car, located at position (-29.9 , 0 ) is traveling at 12.7 m/s ( +x)
Another Car, located at position ( 0, -41.0) is traveling at 6.5 m/s ( +y)

+y Direction
^
|
|
----------> + x direction

Calculate the smallest distance between the two cars

Homework Equations



I created two functions :
p1 (t) = 12.7t - 29.9
p2 (t) = 6.5t - 41.0

Which represent the position of the cars, based on time, relative to the origin




The Attempt at a Solution



Using pythagorean theorom, i concluded the distance between them can be summarized as

d^2 = (p1(t))^2 + (p2(t))^2

Then i Attempt to solve the minumum of this function, which is where i always screw up.

The correct answer to the problem is 22.9 m
 
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Welcome to PF!

Hi RPierre! Welcome to PF! :smile:
RPierre said:
I created two functions :
p1 (t) = 12.7t - 29.9
p2 (t) = 6.5t - 41.0

Which represent the position of the cars, based on time, relative to the origin

Using pythagorean theorom, i concluded the distance between them can be summarized as

d^2 = (p1(t))^2 + (p2(t))^2

Then i Attempt to solve the minumum of this function, which is where i always screw up.

Well, that's fine so far. :smile:

Show us how you tried to solve it, and then we'll be able to see where the problem is. :wink:
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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