Tricky track problem (continued)

  • Thread starter Thread starter Ravnus9
  • Start date Start date
  • Tags Tags
    Track
AI Thread Summary
The discussion revolves around a challenging track problem involving Newton's second law, where the user struggles with having more unknowns than equations. Key points include the role of friction in energy loss and the necessity to account for various forces like gravity, normal force, and spring force. It is suggested to break the problem into smaller sections for better clarity and to seek assistance from teachers or peers for additional insights. The solution involves deriving a second-order nonlinear differential equation that can only be solved numerically. Persistence and methodical analysis are emphasized as crucial to overcoming the difficulties presented by the problem.
Ravnus9
Messages
8
Reaction score
0
Ok here is the track problem again except this time drawn out with some of my work... this is using Newtons second law... i used microsoft word to draw the track and spring so its a little ruff but you get the idea... still could use some help no matter which way i do it i end up getting one more unknown than i have equations... which is getting extremely old, please help, THANK YOU.
Nathan
 

Attachments

Physics news on Phys.org
Nathan,

This problem is not easy at all, and I wonder how your teacher would solve it. Let us know what he said about the solution.

Energy is not conserved because of friction. The work of friction diminishes the mechanical energy. Friction is proportional to the normal force N, but the normal force depends on the speed of the collar, as the sum of the normal component of gravity and that of the spring force plus the normal force N from the track must be equal to the centripetal force, mv^2/R. The tangential acceleration of the collar is determined by the tangential components of gravity and spring force minus friction, which is proportional to N. You can plug in the expression for N from the previous equation and you get a second order nonlinear differential equation for the angle theta. This equation can be solved only numerically by a program. You find such program in Mathematica but there are others, or you can write yours, applying Newton's method, or the more sophisticated Runge-Kutta method.

ehild
 


Hi Nathan,

Thank you for providing more information about the track problem. I can see that you have put in a lot of effort and have used Newton's second law to try and solve it. It can definitely be frustrating when we end up with more unknowns than equations, but don't give up just yet. There are a few things we can try to help us solve this problem.

Firstly, make sure you have clearly identified all the forces acting on the object on the track. This includes the force of gravity, the normal force, and the force of the spring. Also, don't forget about the friction force, which may also be present depending on the surface of the track.

Secondly, try breaking down the problem into smaller parts. Instead of trying to solve the entire track at once, focus on one section at a time. This may help you to better understand the forces and equations involved.

Lastly, don't be afraid to ask for help from a teacher or classmate. Sometimes a fresh pair of eyes can help us see things that we may have missed. Keep practicing and don't give up, you'll get there eventually. Good luck!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top