- #1

lovemake1

- 149

- 1

## Homework Statement

sec^2x - 3secx + 2 < 0

## Homework Equations

## The Attempt at a Solution

sec^2x - 3secx + 2 < 0

ok so this can be written as, (secx - 2)(secx -1) < 0

this means secx is between 1 and 2 right ?

secx = 2 and secx = 1

would we find all the solutions that's between 1 and 2 ?

please check if my understanding is correct.