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I have finally graduated to trig and the six basic functions and how they relate. What I'm having a problem with is this:

**sin/1+cos = 1-cos/sin**

How is this true? I've done every algebraic manipulation I can think of, but I can't see how this can be. I'll show what I have come up with, using the fact that sin x =y/r and cos x =x/r.

It should break down like this:

**(y/r)/1+(x/r) = [1-(x/r)]/(y/r)**

Now, here's how I approached it: Left of the equals sign

**(y/r)/1+(x/r) = y/(r+x)**

Then right of the equals sign:

**[1-(x/r)]/(y/r) = (r-x)/y**

So when does y/(r+x) ever equal (r-x)/y? Thanks for any help provided. And I hope this wasn't too simple for you guys to consider answering.