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Trigonometric Substitution Problem - Calculus 2

  1. Feb 5, 2009 #1
    Hey there
    This is a trig substitution for my Calculus 2 class and I really have NO idea how to get started...


    My professor has yet to go over how to evaluate trigonometric substitutions with coefficients in front of variables.
  2. jcsd
  3. Feb 5, 2009 #2
    how about factoring out the 2?
  4. Feb 6, 2009 #3
    How would you factor out the two?

    Because [tex]\sqrt{3-2x^2}[/tex] is not the same as 2*[tex]\sqrt{\frac{3}{2}-x^2}[/tex]
  5. Feb 6, 2009 #4
    Yes, but [tex] \sqrt{3-2x^2} = \sqrt{2}*\sqrt{\frac{3}{2}-x^2} [/tex]. I may not have been clear in my previous post.
  6. Feb 6, 2009 #5
    Oh! Duh! Thank you!!!
    I'll give it a try.
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