Trigonometry, find solutions between [0/2pi]

  • Thread starter Thread starter synergix
  • Start date Start date
  • Tags Tags
    Trigonometry
AI Thread Summary
To solve the equation tan(x) = 3cot(x) within the interval [0, 2π], one approach is to express cotangent in terms of tangent, leading to tan(x) = 3/tan(x). This can be rearranged to tan^2(x) = 3, allowing for the calculation of solutions using the inverse tangent function. Additionally, the identity sin^2(x) + cos^2(x) = 1 may assist in verifying the solutions. The intersection of the functions tan(x) and 3cot(x) can be visualized graphically to confirm the points of intersection. Ultimately, the solutions can be found by determining the angles where these conditions hold true.
synergix
Messages
177
Reaction score
0

Homework Statement


solve, finding all solutions between [0,2pi]
tanx=3cotx

The Attempt at a Solution



It looks like a relatively simple problem if one knew what they were doing unfortunately I do not. I am trying to think of this graphically and I figure that the places were tanx=3cotx are where the functions intersect. but how do i figure out the values?
 
Physics news on Phys.org
I would think about decomposing tan and cot in their sin & cos components and then work from there. Maybe sin^2(x)+cos^2(x)=1 might be helpful, who knows ;)
 
cotx = 1 / tanx
 
got it thx
 
Back
Top