Trigonometry Question: Solving sin90 + tan45 | Understand the Solution

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The discussion centers on the calculation of sin 90° and tan 45°, with the original poster claiming the answer is 0, while the textbook states it is 2. The correct values are clarified: sin 90° equals 1 and tan 45° equals 1, leading to the correct sum of 2. The confusion arose from a misunderstanding of the unit circle values, particularly regarding sin 90°. The thread emphasizes the importance of accurately referencing trigonometric values to solve such problems correctly.
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Homework Statement



sin90degrees +tan45degrees

Homework Equations





The Attempt at a Solution


my answer is 0 but my textbook says its 2. I don't understand how 2 is the answer.
 
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What is sin 90°? tan 45°? How exactly did you get those answers?
 
I am supposed to use the values from the unit circle. so sin90degrees would = -1
 
Really? Make sure you're going in the right direction.
 
oh silly mistake. thanks alot
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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