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Homework Help: Trivial question on Fourier Series

  1. Jan 17, 2009 #1

    That is what I know, what I'm after is what do I do if my limits are different?

    i.e I'm trying to do this in the interval of [tex]pi/4<x<3pi/4[/tex]

    obviously this isnt a case of -L<x<L

    So I can't have a coefficient of 1/L outside the integral, what is my coefficient?
  2. jcsd
  3. Jan 17, 2009 #2
    I imagine I could integrate from 0<x<3pi/4 with my coefficient being 8/3pi, then minusing the integral from 0<x<pi/4, with a coefficient of 8/pi.
  4. Jan 17, 2009 #3
    Doesn't seem right though, my soln was closer when I knew I was doing it wrong

    According to the solution I'm trying to get, it looks like I should be integrating the whole thing with a coefficient of 2/pi, can anyone confirm why this is please?

    EDIT: nevermind, i think I have it

    the original form took: L - -L = 2L, and did 2/2L = 1/L for the coeffiecient. So I did this. 3pi/4 - -pi/4 = pi (i.e pi=2L), so 2/pi.
    Last edited: Jan 17, 2009
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