Trouble Determining Moment Arm (aka Lever Arm)

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SUMMARY

The discussion centers on determining moment arms in a torque problem involving forces F1 and F2. Participants emphasize the importance of breaking down these forces into their x and y components using trigonometric functions: F2x = F2cos(A2), F2y = F2sin(A2), F1x = F1cos(A1), and F1y = F1sin(A1). The correct identification of angles and the application of right triangle properties are crucial for accurately calculating the lengths of the moment arms. Ultimately, the original poster successfully solved the problem by applying these methods.

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Homework Statement


1.png


Homework Equations


ΣM=Στ

The Attempt at a Solution


I know how to get the net torque about point P, but I am having difficulty determining where the moment arms for each force should be. I did 9 simpler questions before this no problem, but this diagram is a bit more complicated and I'm having trouble with it. The last three questions I have to do are all exactly the same (this one) with different numbers, so some help would be greatly appreciated!

I know the moment arm is the perpendicular distance from the line of action of the force to the point of rotation.

I am confused as how to find the length of the moment arms in this particular diagram. I think they should look like this (orange and blue lines)
1.png


But I am lost as to how to get their lengths (if where I have them is even correct).
 
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Hi,

Perhaps you could try to divide the forces F2 and F1 in the x and y directions.

Such that F2x = F2cos(A2), F2y = F2sin(A2), F1x = F1cos(A1), and F1y = F1sin(A1).

Hence, Your free body diagram would look a little like the attached picture.

Hope this answers your question!
 

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  • P_20160304_123415.jpg
    P_20160304_123415.jpg
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Look at the point where your blue line crosses the horizontal line at the bottom of the rectangle .

What do you know about the two acute angles there ?

What do you know about the sum of the angles in right angle triangles ?.
 
Last edited:
ShraZam said:
Hi,

Perhaps you could try to divide the forces F2 and F1 in the x and y directions.

Such that F2x = F2cos(A2), F2y = F2sin(A2), F1x = F1cos(A1), and F1y = F1sin(A1).

Hence, Your free body diagram would look a little like the attached picture.

Hope this answers your question!
I've tried this a few time and I haven't been able to get the correct answer :(
Do you spot a mistake I could have made?
If you can't read my writing I can type it out!
IMG_0270.jpg
 
Nidum said:
Look at the point where your blue line crosses the horizontal line at the bottom of the rectangle .

What do you know about the two acute angles there ?
I'm not sure, are they supposed to be the same?

Nidum said:
What do you know about the sum of the angles in right angle triangles ?.
They add up to 180 degrees.
 
This is messy, sorry, but I'm at this point in trying to figure the question out!
IMG_0271.jpg
 
Last edited:
Yes - they are the same . So what is the angle between your blue line and the left vertical line of the rectangle at point P ?
 
Nidum said:
Yes - they are the same . So what is the angle between your blue line and the left vertical line of the rectangle at point P ?
38.3 degrees
 
Yes - that angle and angle A1 are the same . Quick bit of trig now will give you length of blue line ?
 
  • #10
Hint : Work out the base length of the triangle below point P .
 
  • #11
Nidum said:
Hint : Work out the base length of the triangle below point P .
Tried it this way, still not getting correct answer
IMG_0272.jpg
 
  • #12
1-png.96777.png


This was your best diagram . Put in the actual dimensions and angles as given and add those that you have worked out so far .

Label all points where lines meet or cross . Simple a , b , c --- will suffice .
 
Last edited:
  • #13
ShraZam said:
Hi,

Perhaps you could try to divide the forces F2 and F1 in the x and y directions.

Such that F2x = F2cos(A2), F2y = F2sin(A2), F1x = F1cos(A1), and F1y = F1sin(A1).

Hence, Your free body diagram would look a little like the attached picture.

Hope this answers your question!

Nidum said:
This was your best diagram . Put in the actual dimensions and angles as given and add those that you have worked out so far .

Label all points where lines meet or cross . Simple a , b , c --- will suffice .

I eventually solved it using the first method I tried (breaking into x and y components.
Thanks for your help.
IMG_0275.jpg
 

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