Trouble finding velocity equation

AI Thread Summary
The discussion revolves around finding the velocity equation from the given acceleration function a(t) = C*t, where C is a constant (1.2 m/s^3). The user is unsure if they can integrate to find the velocity after 3.6 seconds, given that the velocity at 1.0 second is 5.0 m/s. They attempted integration but did not arrive at the correct answer, suspecting they might have omitted the constant of integration. To solve the problem, they need to integrate the acceleration equation, use the known velocity to determine the constant, and then apply it to find the velocity at 3.6 seconds. The discussion emphasizes the importance of correctly applying integration and accounting for constants in the process.
jjlandis
Messages
12
Reaction score
0

Homework Statement


The problem given has a(t) = C*t where C is a constant and equals 1.2 m/s^3 and t is time. It says velocity after 1.0 second is 5.0 m/s. The question is, what is the velocity after 3.6 seconds. I don't know if I can integrate to get the velocity equation or not. Please help.
Thanks!


Homework Equations


a(t) = C*t



The Attempt at a Solution


I tried to integrate to get the velocity equation from the acceleration equation given and solving from there but was not the right answer.
 
Physics news on Phys.org
Find integration. Using the value of velocity( 5m/s) and time(1s) find the constant of integration. Repeat the integration for 3.6s and put the calculated constant of integration to get the final answer.
 
Thank you for the help. I believe I was leaving out the constant that is added to the equation when integrating. Thanks again!
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Two Equations for Average Velocity?
Replies
2
Views
2K
Using Momentum Principle to Find Ratio of Speeds?
Replies
4
Views
1K
Solving for Work Done When Accelerating a Mass
Replies
3
Views
711
Confused about kinematic equations
Replies
20
Views
2K
Find the initial velocity ##U##
Replies
3
Views
806
Truck accelerating down a ramp
Replies
10
Views
955
Energy of particle in simple harmonic motion
Replies
13
Views
1K
Motion of an Object: Displacement & Average Velocity
Replies
8
Views
2K
Velocity equation and distance problems
Replies
13
Views
2K
Is this projectile motion situation possible?
Replies
6
Views
947

Hot Threads

Recent Insights

Back
Top