Trouble understanding bond shifting

  • Thread starter Thread starter AlvisPrabhu
  • Start date Start date
  • Tags Tags
    Bond
AI Thread Summary
The discussion centers on the understanding of lone pairs and bond shifting in the context of the reaction between C2H7O and water. The oxygen atom in C2H7O is described as having three bonded electrons and two unbonded electrons, leading to instability. When C2H7O reacts with water, water acts as a Brønsted base, accepting a proton (H+) and forming H3O+. This reaction results in the production of ethyl alcohol and H3O+. The explanation clarifies the role of lone pairs and bond shifting in this chemical process.
AlvisPrabhu
Messages
17
Reaction score
2
Hello there ,
I am unable to understand the presence of lone pair and also the bond shifting . It would be a great help if anybody could help me understand this.
1521074359986.jpg
 

Attachments

  • 1521074359986.jpg
    1521074359986.jpg
    24.1 KB · Views: 1,155
Chemistry news on Phys.org
initially in C2H7O, oxygen atom has 3 bonded and 2 un-bonded electrons. which makes it quite unstable. When it reacts with water, water acts as bronsted base and accepts an H+ ion and becomes H30+. in this way product comes out to be ethyl alcohol and H3O+.
 
  • Like
Likes AlvisPrabhu
Sultan Abdullah said:
initially in C2H7O, oxygen atom has 3 bonded and 2 un-bonded electrons. which makes it quite unstable. When it reacts with water, water acts as bronsted base and accepts an H+ ion and becomes H30+. in this way product comes out to be ethyl alcohol and H3O+.
Thanks .i got it!
 
It seems like a simple enough question: what is the solubility of epsom salt in water at 20°C? A graph or table showing how it varies with temperature would be a bonus. But upon searching the internet I have been unable to determine this with confidence. Wikipedia gives the value of 113g/100ml. But other sources disagree and I can't find a definitive source for the information. I even asked chatgpt but it couldn't be sure either. I thought, naively, that this would be easy to look up without...
I was introduced to the Octet Rule recently and make me wonder, why does 8 valence electrons or a full p orbital always make an element inert? What is so special with a full p orbital? Like take Calcium for an example, its outer orbital is filled but its only the s orbital thats filled so its still reactive not so much as the Alkaline metals but still pretty reactive. Can someone explain it to me? Thanks!!
Back
Top