Trouble understanding the Gamma function

AI Thread Summary
The Gamma function, defined as Γ(z) = ∫₀^∞ t^(z-1)e^(-t) dt, has poles at non-positive integers and is finite elsewhere. For non-integer values of z less than 0, the integrand approaches infinity as t approaches 0, leading to confusion about the function's behavior in this region. The integral is finite for z with a positive real part, and the Gamma function is extended to other values using analytic continuation, maintaining the relation Γ(z+1) = zΓ(z). This allows the function to be defined across the complex plane despite its poles. Understanding these properties clarifies the function's behavior and resolves concerns about its finiteness for negative non-integer values.
vcdfrexzaswq
Messages
5
Reaction score
0
The http://en.wikipedia.org/wiki/Gamma_function" is the integral \Gamma(z)=\int_{0}^{\infty}{dt\, t^{z-1}e^{-t}} . It has poles for integers of z less than 1 and is finite everywhere else. But to me it seems like it should be infinite for non integer values of z less than 0.

My reasoning: when t is close to 0, the function t^{z-1}e^{-t} is approximately equal to t^{z-1}.

The integral \int_{t_1}^{t_2}{dt\, t^{z-1}} is equal to (t_2^{z} - t_1^{z})/z. When z<0 and t_1 = 0, t_1^{z} is infinite. Thus it seems the integral \int_{0}^{\infty}{dt\, t^{z-1}e^{-t}} has an infinite contribution right after t=0 for z<0.
 
Last edited by a moderator:
Mathematics news on Phys.org
properties of the integrand may be seen by expanding it into a Laurent series
 
vcdfrexzaswq said:
The http://en.wikipedia.org/wiki/Gamma_function" is the integral \Gamma(z)=\int_{0}^{\infty}{dt\, t^{z-1}e^{-t}} .

Only when z has positive real part. It is extended to the rest of the complex plane by analytic continuation or, equivalently, by enforcing that \Gamma(z+1)=z\Gamma(z) holds everywhere.
 
Last edited by a moderator:
gel said:
Only when z has positive real part. It is extended to the rest of the complex plane by analytic continuation or, equivalently, by enforcing that \Gamma(z+1)=z\Gamma(z) holds everywhere.

Ok thanks
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Back
Top