Trouble with normalizing a wave function

marineric
Messages
10
Reaction score
0

Homework Statement


A particle of mass m is in the state ψ(x,t) = Ae-a[mx2/h-bar)+it]

Find A

Homework Equations


I know that to normalize a wave function I should use ∫ψ2 = 1


The Attempt at a Solution


The book gives the solution as 1 = 2abs(A)2∫ e-2amx2/h-bar) dx

My question is where does the "2" factor in front of the A2 come from?
 
Physics news on Phys.org
Hmm...could you perhaps provide a little more information on
(i) the domain of the wavefunction
(ii) the bounds of that integral
 
i) the domain is for all x and t > 0?

ii) the bounds of the integral are from 0 to ∞
 
I think I got it. The solutions manual integrated from 0 to ∞, and multiplied by 2 because of symmetry (to get the -∞ to 0 part)
 
marineric said:
I think I got it. The solutions manual integrated from 0 to ∞, and multiplied by 2 because of symmetry (to get the -∞ to 0 part)
Yup, seems like it. It is rather odd of them to do that though; usually we like -∞ to ∞ bounds because they allow us to use the Gaussian integration formula.
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
Back
Top