Trouble with Solving a Differential Equation

xxdrossxx
Messages
8
Reaction score
0
I'm having trouble with the following textbook problem:

A model for learning in the form of a differential equation is seen below:
\frac{dP}{dt} = k(M - P)
where P(t) measures the performance of someone learning a skill after a training time t, M is the maximum level of performance, and k is a positive constant. Solve this differential equation for P(t). What is the limit of this expression?

The only basic approach for solving differential equations that I know is to "separate and integrate", that is, have one side with P's and a dP, and the other side with t's and a dt (constants anywhere throughout), and then integrate both sides. So, what I was hoping to get was kM * something * dt = kP * something * dP. However, it looks like that's not going to happen. Could someone help me solve this thing?

I know that if "M is the maximum level of performance", then logically \lim_{t \rightarrow \infty} P(t) = M. However, I'm still not sure how to actually find the function P(t).

Thanks for any help you can give. :smile:
 
Last edited:
Physics news on Phys.org
xxdrossxx said:
I'm having trouble with the following textbook problem:



The only basic approach for solving differential equations that I know is to "separate and integrate", that is, have one side with P's and a dP, and the other side with t's and a dt (constants anywhere throughout), and then integrate both sides. So, what I was hoping to get was kM * something * dt = kP * something * dP. However, it looks like that's not going to happen. Could someone help me solve this thing?

I know that if "M is the maximum level of performance", then logically \lim_{t \rightarrow \infty} P(t) = M. However, I'm still not sure how to actually find the function P(t).

Thanks for any help you can give. :smile:


It's easily separable just divide by by M-P and you have a pretty standard integral to find the function P.
 
d_leet said:
It's easily separable just divide by by M-P and you have a pretty standard integral to find the function P.
Ah, of course! I guess my first mistake was distributing the k. Dividing brings me to \frac{dP}{M - P} = kdt, and integrating both sides gives me -ln|M - P| = kt + c. Going from there:

ln|M - P| = -kt - c
e^{-kt - c} = M - P
P = M - e^{-kt - c}
I think I'm doing something very wrong here. The answer in the back of the book is P(t) = M - Me^{-kt}.

I'm thinking I've made a really stupid mistake, but I can't find it. Can anyone help?
 
Last edited:
Have you left out part of the problem- like, say, the information that the subject knew nothing to start with? That is, that P(0)= 0.

P(t) = M - e^{-kt - c}= M- (e^{-c})e^{-kt}
and we can write that as
P(t)= M- C e^{-kt}
where C= e^{-c}.

Then, if P(0)= 0,
P(0)= M- Ce^0= M- C= 0
so C= M.

Actually that's not relevant to the final question: what is the limit of P(t) as t goes to infinity? That answer does not depend on C.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top