Troubleshooting a Current Divider Circuit for Dimmer Lights

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Discussion Overview

The discussion revolves around troubleshooting a current divider circuit designed for dimming lights. Participants explore the behavior of the circuit when adjusting potentiometers and the implications for lamp brightness. The scope includes practical circuit design, electrical components, and safety considerations.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • Glenn describes an issue where increasing the resistance of one potentiometer causes other lamps to brighten, questioning why this occurs if their resistances remain constant.
  • Some participants suggest that the output voltage of the transformer may vary with the adjustment of a potentiometer, potentially explaining the change in brightness of the other bulbs.
  • Concerns are raised about the internal resistance of the battery in the trial version, which could affect circuit performance.
  • Safety considerations regarding the transformer version are discussed, particularly the need to ensure the transformer is rated appropriately for the load.
  • There is a discussion about the heat generated by resistive dimmers, with a participant noting that they can become quite warm and may pose a safety risk if not properly housed.
  • One participant mentions that filament lamps increase in resistance as they heat up, which complicates the dimming process and can lead to significant power dissipation in the dimmer.

Areas of Agreement / Disagreement

Participants express various concerns and hypotheses about the circuit's behavior, but no consensus is reached on the underlying cause of the issue or the best solutions. Multiple competing views regarding the effects of resistance and safety considerations remain present.

Contextual Notes

Participants highlight limitations related to the assumptions about transformer output and the effects of internal resistance in batteries. The discussion also touches on the efficiency of resistive dimmers and their thermal management, which are not fully resolved.

Who May Find This Useful

This discussion may be useful for individuals interested in circuit design, particularly those working with dimmer circuits and seeking to understand the implications of component selection and safety in practical applications.

GPT
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Hello all,
I'm attempting to create a dimmer circuit for some lights Id like to install in my room. I've attached the diagram below.

Heres the problem: When I increase the resistance of potentiometer 2, for example, to decrease the current lamp 2 receives (thus dimming the lamp) the other lamps brighten. I want the other lamps to maintain their luminous output at a constant level dependent upon the amount of resistance of their respective pots.

Bear with me (this is my first circuit) but I don't understand why this is happening.

Two Questions
1) If the resistances of all the other pots remain the same, the same amount of current should flow through them, no? Why are they getting more current?
2) What are potential solutions to this problem?

Thanks for your help
Glenn

Edit:
Here are the parts I'm using on the breadboard:
-12v battery; 12v, 60mA mini indicator lamps; 10k ohm, .5W pot; 300ohm, .5W resistor in series with lamp and pot

These are the parts Id like to use in the finished circuit:
-12v transformer (wired to mains); 12v, 35W MR16 halogen lamps, appropriate pots and resistors
 

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GPT said:
Hello all,
I'm attempting to create a dimmer circuit for some lights Id like to install in my room. I've attached the diagram below.

Heres the problem: When I increase the resistance of potentiometer 2, for example, to decrease the current lamp 2 receives (thus dimming the lamp) the other lamps brighten. I want the other lamps to maintain their luminous output at a constant level dependent upon the amount of resistance of their respective pots.

Bear with me (this is my first circuit) but I don't understand why this is happening.

Two Questions
1) If the resistances of all the other pots remain the same, the same amount of current should flow through them, no? Why are they getting more current?
2) What are potential solutions to this problem?

Thanks for your help
Glenn

Edit:
Here are the parts I'm using on the breadboard:
-12v battery; 12v, 60mA mini indicator lamps; 10k ohm, .5W pot; 300ohm, .5W resistor in series with lamp and pot

These are the parts Id like to use in the finished circuit:
-12v transformer (wired to mains); 12v, 35W MR16 halogen lamps, appropriate pots and resistors

If you measure the output voltage of the transformer as you vary a pot, does it vary? That would explain why the other bulbs change when you vary one pot. It would be because the output resistance of the transformer is not negligible in your circuit.
 
Actually his trial version uses a battery, even more likely candidate for internal resistance I'd say, especially if the battery is "tired".

By the way, what about safety on the transformer version - need to be sure of the transformer rating, and with 35W lamps those "appropriate" pots may run a bit warm.
 
By run a bit warm, do you mean warm enough to be a fire hazard, or too warm to touch?
Is there a formula I can use to calculate the heat dissipated by the pot and its accompanied fixed resistor?
 
What I really meant was that resistive dimmers for 35W bulbs have to be fairly substantial, and mounted in suitable housings to deal with the heat to avoid burnt fingers. Resistive dimmers are generally pretty inefficient, and for this reason they are not so often used nowadays.

Unfortunately, filament lamps undergo a large increase in resistance as they heat up. Thus when you reduce the lamp voltage for dimming, the lamp resistance falls noticeably. Due to this effect, at some settings a dimming resistor may end up dissipating more than half of the lamp's nominal wattage. (If the lamp's resistance were constant, the dimmer could only dissipate up to half power). I'm sorry that I don't have a formula for this, perhaps it's safest to rate the pot for the full wattage.
 

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