- #1

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- 140

## Homework Statement

I'm having a bit of trouble understanding something from this:

http://gyazo.com/88a466b57d8516d2df1b12008947be43

## Homework Equations

## The Attempt at a Solution

I understand how to get the components of reaction at ##A## as well as the tension in segment ##BE##.

What I'm having trouble with is the FBD of the pulley used to determine the tension in ##DEC##. I'm not quite sure how they have come up with a part of the force equation, namely:

##\sum F_z = 0 \Rightarrow 2(\frac{4}{\sqrt{96}})T - \frac{1}{\sqrt{5}}(1677.05) = 0##

The term ##2(\frac{4}{\sqrt{96}})T## is what is confusing. I understand you need twice the tension since it's symmetric, but how on Earth are they getting ##\frac{4}{\sqrt{96}}##?

I figure they are applying ##\frac{T_z}{T} = \frac{4}{\sqrt{96}}## to a triangle, but I'm not seeing the triangle.