True mass, different weights, and the force of gravity

Click For Summary
SUMMARY

The discussion centers on the calculation of an astronaut's weight on a new planet with a mass 2.5 times that of Earth and a radius 1.2 times larger. The astronaut's scale reads 60.0 kg on Earth, but on the new planet, the scale displays 103.4 kg due to the increased gravitational force of 16.9 N/kg. The true mass of the astronaut remains constant at 60.0 kg, as scales measure weight, not mass, which can lead to confusion regarding the terminology used in the question.

PREREQUISITES
  • Understanding of gravitational force equations, specifically F=mg/r^2
  • Knowledge of mass and weight distinctions in physics
  • Familiarity with the gravitational constant (G) and its application
  • Basic understanding of planetary mass and radius effects on gravity
NEXT STEPS
  • Study the implications of gravitational force variations on different celestial bodies
  • Learn about the gravitational constant (G) and its significance in physics
  • Explore the differences between mass and weight in various gravitational fields
  • Investigate the effects of planetary radius on gravitational acceleration
USEFUL FOR

Students in physics, educators teaching gravitational concepts, and anyone interested in the effects of gravity on mass and weight in different planetary environments.

sdoi
Messages
37
Reaction score
0

Homework Statement


An astronaut enters a rocket ship and gets blasted to another planet. The mass of the planet is 2.5 times as large as the mass of Earth, and the radius is 1.2 times as large as Earth's. If the astronauts scale at home says "60.0kg", what will it say on the new planet? In which case does the scale display his true mass and why?


Homework Equations


F=mg/r^2


The Attempt at a Solution


i was able to find the weight of the astronaut on the new planet without any problems:
m(planet)= m(earth) x 2.5
m(planet)= 1.48x10^25 kg

r(planet)= r(earth) x 1.2
r(planet)= 7.65x10^6m

find mass of astronaut:
F=Gm/r^2
g=Gm/r^2
= (6.67x10^-11)(5.97x10^24)/ (6.38x10^6)^2
=9.8N/kg
m= 60.0kg/ 9.8N/kg
m=6.12N

g= Gm/r^2
= (6.67x10^-11)(1.49x10^25)/ (7.65x10^6)^2
= 16.9 N/kg

W=mg
= (6.12N)(16.9 N/kg)
Therefore the atronaut would read 103.4kg on the scale while on the new planet.

For the second part of the question I'm just a little confussed. It asks which scale displays his true mass, but a scale doesn't display mass, it displays weight. Is this part a trick question?
 
Physics news on Phys.org
I would say the scale shows the true mass on earth. In fact, it measures weight, but from the measured weight, it calculated the mass and shows it. But it works only on earth.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 2 ·
Replies
2
Views
4K
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
4
Views
2K
Replies
5
Views
3K
  • · Replies 12 ·
Replies
12
Views
4K
Replies
11
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K