True or false: If it's true, give an example. If it's false, prove it.

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Homework Statement


A function f: R -> R such that f is continuous at a point c if and only if c is not an element of the set: { m\2^n: m,n in Z, n>=0)


Homework Equations


Definition of continuity/discontinuity?


The Attempt at a Solution


Is it enough to say that we can define a piecewise function where f(x) = 0 if x is an element of the described set, and f(x) = x otherwise...then we maybe have continuity at points such as irrational numbers?
 
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davitykale said:

Homework Statement


A function f: R -> R such that f is continuous at a point c if and only if c is not an element of the set: { m\2^n: m,n in Z, n>=0)


Homework Equations


Definition of continuity/discontinuity?


The Attempt at a Solution


Is it enough to say that we can define a piecewise function where f(x) = 0 if x is an element of the described set, and f(x) = x otherwise...then we maybe have continuity at points such as irrational numbers?

I would be if you could prove it. But you can't. The set you've defined is dense. It doesn't work. Try f(m/2^n)=1/2^n for points in the set and zero otherwise.
 
I think I'm confused...wouldn't that mean that c is continuous when it is an element of the given set?
 
davitykale said:
I think I'm confused...wouldn't that mean that c is continuous when it is an element of the given set?

No, it's not continuous at points of the form m/2^n. There's an irrational in every neighborhood of one of those points.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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