Trying to figure how fast you would be falling after 268 feet?

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The discussion focuses on calculating the speed of a fall from 268 feet, with an initial velocity of zero and ignoring air resistance. The formula used is vf^2 = vi^2 + 2*a*d, where the acceleration due to gravity is approximated at 9.81 m/s². The initial calculation mistakenly uses 90 meters instead of the correct conversion of 268 feet to 81.7 meters. After correcting the distance, the final speed should be recalculated, leading to a different result than the initially suggested 93.9 mph. Accurate conversions and calculations are essential for determining the correct falling speed.
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Trying to figure how fast you would be falling after 268 feet? not worrying about resistance and in terms of weight just and average person... this is what I did.. is it correct? or way off


vf^2 = vi^2 + 2*a*d
vf^2 = 0 + 2* 9.81 * 90
vf^2 = 1765.8m^2/s^2
take square root
vf = 42 m/s then convert to mph multiply by 2.24? 93.9mph
 
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kevindpalmer2 said:
Trying to figure how fast you would be falling after 268 feet? not worrying about resistance and in terms of weight just and average person... this is what I did.. is it correct? or way off


vf^2 = vi^2 + 2*a*d
vf^2 = 0 + 2* 9.81 * 90
vf^2 = 1765.8m^2/s^2
take square root
vf = 42 m/s then convert to mph multiply by 2.24? 93.9mph

This is OK, except that 268 feet is 81.7 meters and not 90
 
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