A train traveling at a velocity of 60.0 m/s is slowed down at a uniform rate of 1.25 m/s2. How far will it travel before its velocity is 1/2 its original value?
v2 = vo2 + 2ad
The Attempt at a Solution
I first need to isolate my variable, so 'd'. In which case, I believe the equation would then look like 'd=vo2 [itex]\div[/itex] v2+2a. Filling in this equation with the numbers then looks like: d=60m/s2[itex]\div[/itex]30m/s2+2(-1.25m/s2). But when I calculate it all out I'm left with d=-0.5m/s2. This does not make any sense though; it's not possible for the train to travel a negative amount of distance. And also, isn't displacement measured in units of length and not time? I can't figure out how to get rid of the seconds. Needless to say, I am very confused. Thanks in advance.