Trying to find force on a chain.

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To determine the force transferred into a drive chain, the motor's power (150HP) and RPM (1750) can be used to calculate torque at the motor. This torque is then multiplied by the gearbox ratio (39:44) to find the torque at the gearbox output shaft. The maximum tension in the chain can be calculated by dividing this torque by the radius of the first sprocket (6 inches). It's important to consider gearbox efficiency, typically assumed at 95%, to adjust the maximum tension accordingly. Actual tension will depend on the load, which may be less than the calculated maximum.
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I am trying to find out how much force is being transferred into a drive chain. Here's the info as I was given:

Motor: 150HP
RPM: 1750
Gearbox information:
ratio: 39:44 Input HP 223 Output shaft to sprocket 6" dia.
Sprocket 20" dia. Top of tooth to bottom of root 1-3/8" 4" pitch of chain
No other sprockets connected.

Am I correct in assuming there is some extraneous info in there? As in, the input HP on the gearbox, I think that's a max number they may have pulled off the id plate?

What we're looking for is the tonnage of the bench.
 
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Is it that I'm not giving enough information? If so, what more information is needed? I'm not an engineer by trade, I'm a mechanical designer, so I don't know what calculation to look up. Can someone at least point me in the right direction here?
 
Pwr & rpm give you torque at the motor. Multiply that by the gear ratio to get torque at the gear box output shaft. Divide that by the radius of the first sprocket to get max tension in the chain. If you have the gear box efficiency, then reduce the number by that amount, otherwise assume 95%.

This is the max chain tension. Actual tension is determined by the load if it is less.
 
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