Trying To help My Daughter With A Physics ?

  • Thread starter Thread starter Forgo
  • Start date Start date
  • Tags Tags
    Physics
AI Thread Summary
In balancing a seesaw with a second child, the weight of the seesaw itself is not relevant if the pivot is placed at its center, as this will not create torque. The seesaw's uniform mass means its weight acts directly on the pivot point, allowing for simplification in calculations. The focus should be on the weights of the children and their distances from the pivot. By applying the principle of moments, the seesaw can be balanced effectively. Understanding these concepts is crucial for solving the problem accurately.
Forgo
Messages
6
Reaction score
0
She has to figure out where to place a second kid on a seesaw to balance the seesaw. They give you the weight of the seesaw in the problem. Is this relevant? Or do you ignore the weight of the seesaw?
 
Physics news on Phys.org
If you place the pivot exactly halfway between the board, and assuming the board is uniform in mass/density, then the force of it's weight will act right on the pivot so it won't cause a torque.. meaning you can pretty much exclude it from the equation
 
Thanks.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'

Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'

Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is（Figure 2）： F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

Seesaw Equilibrium: Examining Forces & Motion
Replies
2
Views
2K
Three people are balanced on a uniform seesaw - Torque
Replies
4
Views
6K
How to Calculate Forces on a Plank with a Weight?
Replies
8
Views
2K
How does a swing demonstrate acceleration changes in both speed and direction?
Replies
2
Views
1K
How Can Physics Calculate Seesaw Dynamics with Unequal Masses?
Replies
8
Views
6K
Three bys trying to balance a seesaw
Replies
1
Views
4K
Seesaw: simple statics problem?
Replies
2
Views
7K
Rotational inertia (moment of inertia)
Replies
1
Views
6K
3 children and a balancing a seesaw
Replies
3
Views
14K
How to Balance a Seesaw with Three Children?
Replies
10
Views
3K

Hot Threads

Recent Insights

Back
Top